Logout Inactive User

Snippet Code

Need to people out if they have been inactive for too long? Do it with this piece of code.

Introduction




This takes 3 functions to complete the inactive session task.



1. We need to check if the person is actually logged in using our isLogged function

2. We need the function to check the time the page loaded, and when the last page was loaded

3. We need a function to log the user out after inactivity.



It is reccomended that you place the 3 functions in the same file, and have this file

included on EVERY page that requires a login to view the page.



Function sessionX() MUST come after session_start()

functions.php




<?php

# Start a session

session_start();

# Check if a user is logged in

function isLogged(){

    if($_SESSION['logged']){ # When logged in this variable is set to TRUE

        return TRUE;

    }else{

        return FALSE;

    }

}



# Log a user Out

function logOut(){

    $_SESSION = array();

    if (isset($_COOKIE[session_name()])) {

        setcookie(session_name(), '', time()-42000, '/');

    }

    session_destroy();

}



# Session Logout after in activity

function sessionX(){

    $logLength = 1800; # time in seconds :: 1800 = 30 minutes

    $ctime = strtotime("now"); # Create a time from a string

    # If no session time is created, create one

    if(!isset($_SESSION['sessionX'])){ 

        # create session time

        $_SESSION['sessionX'] = $ctime; 

    }else{

        # Check if they have exceded the time limit of inactivity

        if(((strtotime("now") - $_SESSION['sessionX']) > $logLength) && isLogged()){

            # If exceded the time, log the user out

            logOut();

            # Redirect to login page to log back in

            header("Location: /login.php");

            exit;

        }else{

            # If they have not exceded the time limit of inactivity, keep them logged in

            $_SESSION['sessionX'] = $ctime;

        }

    }

}

# Run Session logout check

sessionX();

?>

Snippet Comments

Add Your Comment

soul2life
2011-06-02 11:26:47

Nice one. . great!

saudagardinar
2011-05-23 19:26:50

very nice code..thanks

glennbets
2011-02-25 04:12:50

So you mean to say, we can log him out even if we are not the one using his account? Wow!

php scripts
2010-09-14 00:10:54

yeah, you rock buddy. i like this script

php scripts
2010-09-14 00:09:16

This is just what i need but i am unsure what file to add it to and the ones i have added it to gives me error messages!

wotan
2010-02-28 00:00:00

i think that script will automatically logout the user after 15 minutes always! Not only in case of inactivity! How can this script know that user is inactive? And when teh user is doing something and suddenly is logged out thats bad...

BEN
2009-11-16 00:00:00

what would you do to have a popup come at the halfway point to alert you that you have only a few seconds left before you are timed out

Brian
2009-03-24 00:00:00

Thanks for the good tip. I get lots of tips from phpsnips.com.

Admin
2009-01-30 00:00:00

In that case, I would place a query within the function isLogged() right before the FALSE return.

redi
2008-12-18 00:00:00

What if i want to update a field in a database when islogged returns false.

Eg: a field which says online or offline.

Cheers, Just a suggestion

Admin
2008-09-05 00:00:00

This code snippet needs to be at the top of all files where a user needs to be logged in.

so you can place it in a "functions.php" file, then use include = "functions.php"; to connect to it.

Gubbins
2008-08-31 00:00:00

This is just what i need but i am unsure what file to add it to and the ones i have added it to gives me error messages!

randomideas
2008-07-25 00:00:00

You Rock!

Add Your Comment